-(1-5x+3x^2)=x(3-2x)

Solution for -(1-5x+3x^2)=x(3-2x) equation:

-(1-5x+3x^2)=x(3-2x)

We move all terms to the left:

-(1-5x+3x^2)-(x(3-2x))=0

We add all the numbers together, and all the variables

-(1-5x+3x^2)-(x(-2x+3))=0

We get rid of parentheses

-3x^2+5x-(x(-2x+3))-1=0


We calculate terms in parentheses: -(x(-2x+3)), so:

x(-2x+3)

We multiply parentheses

-2x^2+3x

Back to the equation:

-(-2x^2+3x)


We get rid of parentheses

-3x^2+2x^2-3x+5x-1=0

We add all the numbers together, and all the variables

-1x^2+2x-1=0

a = -1; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{-2}=1$